Answer
$\dfrac{7ab^{-4}}{7^{-1}a^{-3}b^{2}}=\dfrac{49a^{4}}{b^{6}}$
Work Step by Step
$\dfrac{7ab^{-4}}{7^{-1}a^{-3}b^{2}}$
Evaluate the division:
$\dfrac{7ab^{-4}}{7^{-1}a^{-3}b^{2}}=7^{1-(-1)}a^{1-(-3)}b^{-4-2}=7^{2}a^{4}b^{-6}=...$
Simplify:
$...=49a^{4}b^{-6}=\dfrac{49a^{4}}{b^{6}}$