Answer
$\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}=a^{24}b^{8}$
Work Step by Step
$\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}$
Evaluate the exponential expression:
$\Big(\dfrac{a^{-5}b}{ab^{3}}\Big)^{-4}=\dfrac{a^{20}b^{-4}}{a^{-4}b^{-12}}=...$
Now, evaluate the division and simplify:
$...=a^{20-(-4)}b^{-4-(-12)}=a^{24}b^{8}$