Answer
$\dfrac{-15r^{-6}s}{5r^{-4}s^{-3}}=\dfrac{-3s^{4}}{r^{2}}$
Work Step by Step
$\dfrac{-15r^{-6}s}{5r^{-4}s^{-3}}$
Evaluate the division:
$\dfrac{-15r^{-6}s}{5r^{-4}s^{-3}}=\Big(\dfrac{-15}{5}\Big)r^{-6-(-4)}s^{1-(-3)}=-3r^{-2}s^{4}=...$
Simplify:
$...=\dfrac{-3s^{4}}{r^{2}}$