Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 354: 66

$\dfrac{(rs)^{-3}}{(r^{2}s^{3})^{2}}=\dfrac{1}{r^{7}s^{9}}$

$\dfrac{(rs)^{-3}}{(r^{2}s^{3})^{2}}$ Evaluate the exponential expressions in the numerator and the denominator: $\dfrac{(rs)^{-3}}{(r^{2}s^{3})^{2}}=\dfrac{r^{-3}s^{-3}}{r^{4}s^{6}}=...$ Evaluate the division and simplify: $...=r^{-3-4}s^{-3-6}=r^{-7}s^{-9}=\dfrac{1}{r^{7}s^{9}}$