Answer
$-\dfrac{9}{4}$
Work Step by Step
Given the expression:
$\dfrac{4y-3x+z}{2x+y}$.
Substitute the values $x=−2$, $y=0$, and $z=3$:
$\dfrac{4(0)-3(-2)+3}{2(-2)+0} = -\dfrac{9}{4}$.
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