Answer
$-\frac{5}{6}$
Work Step by Step
Given the expression:
$\frac{x^3-2y+z}{2z}$.
Substitute the values $x=-2$, $y=0$, and $z=3$:
$\frac{(-2)^3-2(0)+3}{2(3)} = -\frac{5}{6}$.
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