Answer
$-\dfrac{5}{3}$
Work Step by Step
Given $\dfrac{x^2-y+2z}{3x} , $ if $x=-2 \ , \ y = 0$ and $z = 3$
$\dfrac{(-2)^2-0+2\times 3}{3\times (-2)} = \dfrac{4+6}{-6} = -\dfrac{10}{6} = -\dfrac{5}{3}$
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