Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 898: 53

Answer

$\frac{17}{4}$

Work Step by Step

Given the expression: $\dfrac{3z-4x+y}{x+2z}$. Substitute the values $x=−2$, $y=0$, and $z=3$: $\dfrac{3(3)-4(-2)+0}{(-2)+2(3)} = \frac{17}{4}$.
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