Answer
$\frac{17}{4}$
Work Step by Step
Given the expression:
$\dfrac{3z-4x+y}{x+2z}$.
Substitute the values $x=−2$, $y=0$, and $z=3$:
$\dfrac{3(3)-4(-2)+0}{(-2)+2(3)} = \frac{17}{4}$.
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