Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 890: 71

Please see the graph.

$f(x)=ln x$ $x=1$ $f(x)=ln x$ $f(1)=ln 1$ $f(1)= 0$ $(1,0)$ $x=2.718$ $f(x)=ln x$ $f(2.718)=ln 2.718$ $f(2.718) = 1$ $(2.718, 1)$ $x=7.389$ $f(x)=ln x$ $f(7.389)=ln 7.389$ $f(7.389)=2$ $(7.389, 2)$ The points $(1,0)$, $(2.718,1)$, and $(7.389,2)$ are on the curve.