Answer
$x=\frac{10^{-0.5}-1}{2}\approx-0.3419$
Work Step by Step
$\log (2x+1)=-0.5$
Rewriting in exponential form, $2x+1=10^{-0.5}$.
Now solving for x:
$2x+1=10^{-0.5}$
$2x=10^{-0.5}-1$
$x=\frac{10^{-0.5}-1}{2}\approx-0.3419$.
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