Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 45



Work Step by Step

$\log (2x+1)=-0.5$ Rewriting in exponential form, $2x+1=10^{-0.5}$. Now solving for x: $2x+1=10^{-0.5}$ $2x=10^{-0.5}-1$ $x=\frac{10^{-0.5}-1}{2}\approx-0.3419$.
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