## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 890: 61

#### Answer

{$\frac{4}{7}$}

#### Work Step by Step

$6x-3(2-5x)=6$ $6x-6+15x=6$ $6x+15x-6=6$ $21x=6+6$ $21x=12$ $x=\frac{12}{21}=\frac{4}{7}$ The solution set for the equation is {$\frac{4}{7}$}

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