Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set: 59

Answer

-2.3219

Work Step by Step

From the change of base formula, we know that $log_{b}a=\frac{log_{c}a}{log_{c}b}$ ($a$, $b$, and $c$ are positive real numbers and neither $b$ nor $c$ is equal to 1). Therefore, $log_{\frac{1}{2}}5=\frac{log_{10}5}{log_{10}\frac{1}{2}}=\frac{0.6990}{-0.3010}=-2.3219$.
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