Answer
Please see the graph.
Work Step by Step
$f(x)=e^{2x}$
$x=0$
$f(x)=e^{2x}$
$f(0)=e^{2*0}$
$f(0)=e^0$
$f(0)=1$
$x=1/2$
$f(x)=e^{2x}$
$f(1)=e^{2*1/2}$
$f(1)=e^1$
$(1/2)=2.718$
$x=1$
$f(x)=e^{2x}$
$f(2)=e^{2*1}$
$f(2)=e^2$
$f(2)=7.389$
The points $(0,1)$, $(.5,2.718)$, and $(1,7.389)$ are on the curve.