Answer
$\frac{2}{x(x+1)}$
Work Step by Step
We simplify as follows:
$\frac{6x+2}{x^{2}-1}\div\frac{3x^{2}+x}{x-1}$
$=\frac{6x+2}{x^{2}-1}\times\frac{x-1}{3x^{2}+x}$
$=\frac{2(3x+1)}{(x-1)(x+1)}\times\frac{x-1}{x(3x+1)}$
$=\frac{2}{x(x+1)}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 12 - Cumulative Review - Page 912: 7
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