Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review - Page 912: 3

Answer

$\frac{1}{x-9}$

Work Step by Step

$\frac{x+9}{x^{2}-81}=\frac{x+9}{x^{2}-9^{2}}=\frac{x+9}{(x-9)(x+9)}=\frac{1}{x-9}$
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