Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review - Page 912: 2

Answer

$\frac{1}{1-x}$

Work Step by Step

$\frac{1}{1-x^{2}}+\frac{x}{1-x^{2}}$ =$\frac{1+x}{1-x^{2}}$ =$\frac{1+x}{1^{2}-x^{2}}$ =$\frac{1+x}{(1+x)(1-x)}$ =$\frac{1}{1-x}$
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