Answer
$\frac{1}{1-x}$
Work Step by Step
$\frac{1}{1-x^{2}}+\frac{x}{1-x^{2}}$
=$\frac{1+x}{1-x^{2}}$
=$\frac{1+x}{1^{2}-x^{2}}$
=$\frac{1+x}{(1+x)(1-x)}$
=$\frac{1}{1-x}$
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