Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Cumulative Review - Page 912: 6



Work Step by Step

$\frac{1}{3}(x-2)=\frac{1}{4}(x+1)$ $4(x-2)=3(x+1)$ $4x-8=3x+3$ $4x-3x-8=3x-3x+3$ $x-8=+3$ $x-8+8=+3+8$ $x=11$
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