Answer
$f(x)=1/3*x+20/3$
Work Step by Step
through $(-2, 6)$ and perpendicular to $f(x) =-3x+4$
Perpendicular lines have slopes whose product is -1.
$-3*m=-1$
$-3m/-3=-1/-3$
$m=1/3$
$y=mx+b$
$y=1/3*x+b$
$6=1/3*-2+b$
$6=-2/3+b$
$6+2/3=-2/3+b+2/3$
$20/3=b$
$y=1/3x+20/3$
$f(x)=1/3x+20/3$