Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Vocabulary and Readiness Check - Page 808: 14

$(10, -7)$

$h(x) =(x-10)^2-7$ For a graph in the form $f(x) = a(x-h)^2+k$, the axis of symmetry is the line $x=h$. $h(x) =(x-10)^2-7$ Axis of symmetry $x=10$ Vertex $x=10$ $h(x) =(x-10)^2-7$ $h(10) =(10-10)^2-7$ $h(10) =0^2-7$ $h(10)=0-7$ $h(10)=-7$