Answer
$(0,3)$
Work Step by Step
$f(x) =2x^2+3$
For a graph in the form $f(x) = a(x-h)^2+k$, the axis of symmetry is the line $x=h$.
$f(x) =2x^2+3$
$f(x) =2(x-0)^2+3$
Axis of symmetry
$x=0$
Vertex
$x=0$
$f(x) =2x^2+3$
$f(0) =2*0^2+3$
$f(0)=2*0+3$
$f(0)=0+3$
$f(0)=3$