Answer
$(-5, 0)$
Work Step by Step
$g(x) =(x+5)^2$
For a graph in the form $f(x) = a(x-h)^2+k$, the axis of symmetry is the line $x=h$.
$g(x) =(x+5)^2$
$g(x) =(x- -5)^2$
Axis of symmetry
$x=-5$
Vertex
$x=-5$
$g(x) =(x+5)^2$
$g(-5) =(-5+5)^2$
$g(-5)=0^2$
$g(-5)=0$