Answer
$(0, -1)$
Work Step by Step
$h(x) =x^2-1$
For a graph in the form $f(x) = a(x-h)^2+k$, the axis of symmetry is the line $x=h$.
$h(x) =x^2-1$
$h(x) =(x-0)^2-1$
Axis of symmetry
$x=0$
Vertex
$x=0$
$h(x) =x^2-1$
$h(0) =0^2-1$
$h(0)=0-1$
$h(0)=-1$