Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Vocabulary and Readiness Check - Page 808: 13

$(-1, 5)$

$g(x) =(x+1)^2+5$ For a graph in the form $f(x) = a(x-h)^2+k$, the axis of symmetry is the line $x=h$. $g(x) =(x+1)^2+5$ $g(x) =(x- -1)^2+5$ Axis of symmetry $x=-1$ Vertex $x=-1$ $g(x) =(x+1)^2+5$ $g(-1) =(-1+1)^2+5$ $g(-1)=0^2+5$ $g(-1)=0+5$ $g(-1)=5$