Answer
Please see the graph.
Work Step by Step
$F(x) = (x-2)^2-3$
Axis of symmetry:
$F(x) = (x-2)^2-3$
$F(x) = (x- 2)^2-3$
$x=2$
Vertex:
$F(x) = (x-2)^2-3$
$F(2) = (2-2)^2-3$
$F(2)=0^2-3$
$F(2) = 0-3$
$F(2)=-3$
The green line $x=2$ is the axis of symmetry, the dot at $(2,-3)$ is the vertex, and the red line is the function $F(x)=(x-3)^2-3$.
