Answer
Please see the graph.
Work Step by Step
$f(x)=x^2-2$
Axis of symmetry:
$f(x)=x^2-2$
$f(x)=(x-0)^2-2$
$x=0$
Vertex:
$f(x)=x^2-2$
$f(0)=0^2-2$
$f(0)=0-2$
$f(0)=-2$
The dot at $(0, -2)$ is the vertex, the black line at $x=0$ is the axis of symmetry, and the red line that goes through the dot is the function $f(x)=x^2-2$.
