Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Practice - Page 809: 19

Please see the graph.

$h(x) = (x-3)^2+2$ Axis of symmetry: $h(x) = (x-3)^2+2$ $h(x) = (x- 3)^2+2$ $x=3$ Vertex: $h(x) = (x-3)^2+2$ $h(3) = (3-3)^2+2$ $h(3)=0^2+2$ $h(3) = 0+2$ $h(3)=2$ The green line $x=3$ is the axis of symmetry, the black dot at $(3,2)$ is the vertex, and the red line is the function $h(x)=(x-3)^2+2$.