Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Practice - Page 809: 13

Please see the graph.

$f(x) = (x-2)^2+5$ Axis of symmetry: $f(x) = (x-2)^2+5$ $f(x) = (x- 2)^2+5$ $x=2$ Vertex: $f(x) = (x-2)^2+5$ $f(2) = (2-2)^2+5$ $f(2)=0^2+5$ $f(2) = 0+5$ $f(2)=5$ The green line $x=2$ is the axis of symmetry, the black dot at $(2,5)$ is the vertex, and the red line is the function $f(x)=(x-2)^2+5$.