Answer
Please see the graph.
Work Step by Step
$G(x) = (x+3)^2+3$
Axis of symmetry:
$G(x) = (x+3)^2+3$
$G(x) = (x- -3)^2+3$
$x=-3$
Vertex:
$G(x) = (x+3)^2+3$
$G(-3) = (-3+3)^2+3$
$G(-3)=0^2+3$
$G(-3) = 0+3$
$G(-3)=3$
The green line $x=-3$ is the axis of symmetry, the black dot at $(-3,3)$ is the vertex, and the red line is the function $G(x)=(x+3)^2+3$.
