#### Answer

This quadratic equation has two complex, but not real solutions.

#### Work Step by Step

Rewrite the quadratic equation into standard form.
$-5x^2+4x-6=0$
$a=-5, b=4, c=-6$
therefore,
$b^2-4ac=(4)^2-4(-5)(-6)$
$=-104$
This quadratic equation has two complex, but not real solutions.