## Algebra: A Combined Approach (4th Edition)

$x=\dfrac{3}{8}\pm\dfrac{\sqrt{87}}{8}i$
$6=-4x^{2}+3x$ Rewrite the equation by taking all terms to the left side of the equation: $4x^{2}-3x+6=0$ Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Here, $a=4$, $b=-3$ and $c=6$ Substitute: $x=\dfrac{-(-3)\pm\sqrt{(-3)^{2}-4(4)(6)}}{2(4)}=\dfrac{3\pm\sqrt{9-96}}{8}=...$ $...=\dfrac{3\pm\sqrt{-87}}{8}=\dfrac{3\pm\sqrt{87}i}{8}=\dfrac{3}{8}\pm\dfrac{\sqrt{87}}{8}i$