#### Answer

This quadratic equation has two real solutions.

#### Work Step by Step

$x^2-5=0$
$a=1, b=0, c=-5$
therefore,
$b^2-4ac=0^2-4(1)(-5)$
$=20$
This quadratic equation has two real solutions.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

This quadratic equation has two real solutions.

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