#### Answer

This quadratic equation has two real solutions.

#### Work Step by Step

Rewrite the quadratic equation into standard form.
$-3x^2-7x+5=0$
$a=-3, b=-7, c=5$
therefore,
$b^2-4ac=(-7)^2-4(-3)(5)$
$=109$
This quadratic equation has two real solutions.