Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set: 26

Answer

$x=-3\pm\sqrt{11}$

Work Step by Step

$x(x+6)=2$ Evaluate the product on the left side of the equation: $x^{2}+6x=2$ Take the $2$ to the left side: $x^{2}+6x-2=0$ Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Here, $a=1$, $b=6$ and $c=-2$ Substitute: $x=\dfrac{-6\pm\sqrt{6^{2}-4(1)(-2)}}{2(1)}=\dfrac{-6\pm\sqrt{36+8}}{2}=...$ $...=\dfrac{-6\pm\sqrt{44}}{2}=\dfrac{-6\pm2\sqrt{11}}{2}=-3\pm\sqrt{11}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.