#### Answer

$y=4\pm3i \sqrt2$

#### Work Step by Step

$(y-4)^2+18=0$
$(y-4)^2=-18$
$\sqrt(y-4)^2=\pm\sqrt-18$
$y-4=\pm 3i\sqrt2$
$y=4\pm3i \sqrt2$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$y=4\pm3i \sqrt2$

$(y-4)^2+18=0$
$(y-4)^2=-18$
$\sqrt(y-4)^2=\pm\sqrt-18$
$y-4=\pm 3i\sqrt2$
$y=4\pm3i \sqrt2$

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