#### Answer

$y=\frac{-1}{2}\pm\frac{5}{4}i$

#### Work Step by Step

$(4y+2)^2=-25$
$\sqrt(4y+2)^2=\pm\sqrt-25$
$4y+2=\pm5i$
$4y=-2\pm5i$
$y=\frac{-1}{2}\pm\frac{5}{4}i$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$y=\frac{-1}{2}\pm\frac{5}{4}i$

$(4y+2)^2=-25$
$\sqrt(4y+2)^2=\pm\sqrt-25$
$4y+2=\pm5i$
$4y=-2\pm5i$
$y=\frac{-1}{2}\pm\frac{5}{4}i$

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