Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Completing the Square - Exercise Set: 13

Answer

$x=\dfrac{3}{2}\pm\sqrt{2}$

Work Step by Step

$(2x-3)^{2}=8$ Take the square root of both sides of the equation: $\sqrt{(2x-3)^{2}}=\pm\sqrt{8}$ $2x-3=\pm2\sqrt{2}$ Solve for $x$: $2x=3\pm2\sqrt{2}$ $x=\dfrac{3\pm2\sqrt{2}}{2}$ $x=\dfrac{3}{2}\pm\sqrt{2}$
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