Answer
$x=\dfrac{3}{2}\pm\sqrt{2}$
Work Step by Step
$(2x-3)^{2}=8$
Take the square root of both sides of the equation:
$\sqrt{(2x-3)^{2}}=\pm\sqrt{8}$
$2x-3=\pm2\sqrt{2}$
Solve for $x$:
$2x=3\pm2\sqrt{2}$
$x=\dfrac{3\pm2\sqrt{2}}{2}$
$x=\dfrac{3}{2}\pm\sqrt{2}$