## Algebra: A Combined Approach (4th Edition)

$x=\frac{1}{3}\pm\frac{4}{3}i$
$(3x-1)^2=-16$ Use the square root property. $\sqrt(3x-1)^2=\pm\sqrt-16$ $3x-1=\pm4i$ The square root of a negative number yields a complex number, denoted as, $i$. $3x=\pm4i+1$ $x=\frac{1}{3}\pm\frac{4}{3}i$