#### Answer

$z=\pm2i\sqrt 2$

#### Work Step by Step

$2z^2+16=0$
$2z^2=-16$
$z^2=-8$
$\sqrt z^2=\pm\sqrt-8$
$z=\pm2i\sqrt2$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$z=\pm2i\sqrt 2$

$2z^2+16=0$
$2z^2=-16$
$z^2=-8$
$\sqrt z^2=\pm\sqrt-8$
$z=\pm2i\sqrt2$

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