Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 746: 49

Answer

$(b^{5/6})/(49c^{5/3}a^{1/4})$

Work Step by Step

$(\frac{49c^{\frac{5}{3}}}{a^\frac{-1}{4}b^\frac{5}{6}})^{-1}$ $(49c^{5/3})^{-1}/(a^{-1/4}b^{5/6})^{-1}$ $1/(49c^{5/3})/1/(a^{-1/4}b^{5/6})$ $((49c^{5/3})/(49c^{5/3}))*1/(49c^{5/3})/1/(a^{-1/4}b^{5/6})$ $(49c^{5/3})/(49c^{5/3})/(49c^{5/3})/(a^{-1/4}b^{5/6})$ $(a^{-1/4}b^{5/6})/(a^{-1/4}b^{5/6})*(49c^{5/3})/(49c^{5/3})/(49c^{5/3})/(a^{-1/4}b^{5/6})$ $(a^{-1/4}b^{5/6})*(49c^{5/3})/(49c^{5/3})/(a^{-1/4}b^{5/6})*(49c^{5/3})/(a^{-1/4}b^{5/6})$ $(a^{-1/4}b^{5/6})*1/1*(49c^{5/3})$ $(a^{-1/4}b^{5/6})/(49c^{5/3})$ $(b^{5/6}/a^{1/4})/(49c^{5/3})$ $(a^{1/4}/a^{1/4})*(b^{5/6}/a^{1/4})/(49c^{5/3})$ $(b^{5/6}*a^{1/4}/a^{1/4})/(49c^{5/3}a^{1/4})$ $(b^{5/6})/(49c^{5/3}a^{1/4})$
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