Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 746: 10



Work Step by Step

$\sqrt {16a^{4}b^{12}}$ =$\sqrt {16}\times\sqrt {a^{4}}\times\sqrt {b^{12}}$ =$\sqrt {4^{2}}\times\sqrt {a^{4}}\times\sqrt {b^{12}}$ =$4\times a^{2}\times b^{6}$ =$4a^{2}b^{6}$
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