Answer
$\frac{9}{4}$
Work Step by Step
Step 1: $(\frac{8}{27})^{-\frac{2}{3}}$
Step 2: $(\frac{2^{3}}{3^{3}})^{-\frac{2}{3}}$
Step 3: $\frac{(2^{3})^{-\frac{2}{3}}}{(3^{3})^{-\frac{2}{3}}}$
Step 4: Simplifying the indexes, $\frac{2^{-2}}{3^{-2}}$
Step 5: Simplifying further, $\frac{3^{2}}{2^{2}}$ = $\frac{9}{4}$
