Answer
$-2x^{3}y^{4}$
Work Step by Step
$\sqrt[5] {-32x^{15}y^{20}}$
=$\sqrt[5] {-32}\times \sqrt[5] {x^{15}}\times \sqrt[5] {y^{20}}$
=$\sqrt[5] {(-2)^{5}}\times \sqrt[5] {x^{15}}\times \sqrt[5] {y^{20}}$
=$-2\times x^{3} \times y^{4}$
=$-2x^{3}y^{4}$
