Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 12

Answer

$-2x^{3}y^{4}$

Work Step by Step

$\sqrt[5] {-32x^{15}y^{20}}$ =$\sqrt[5] {-32}\times \sqrt[5] {x^{15}}\times \sqrt[5] {y^{20}}$ =$\sqrt[5] {(-2)^{5}}\times \sqrt[5] {x^{15}}\times \sqrt[5] {y^{20}}$ =$-2\times x^{3} \times y^{4}$ =$-2x^{3}y^{4}$
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