#### Answer

$\frac{3y}{z^{4}}$

#### Work Step by Step

$\sqrt[3] \frac{27y^{3}}{z^{12}}$=$\sqrt[3] \frac{3^{3}\times y^{3}}{(z^{4})^{3}}$=$\frac{3y}{z^{4}}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{3y}{z^{4}}$

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