Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Appendix B - Exercise Set: 40

Answer

$y = -3$ or $y =+5$

Work Step by Step

$\frac{y^2}{30} = \frac{y}{15} + \frac{1}{2}$ Step 1: Clear the equation from fractions. $30(\frac{y^2}{30}) = 30(\frac{y}{15} + \frac{1}{2})$ Step 2: Use the distribute property. $y^2 = 2y + 15$ Step 3: is not needed since no simplifying can be done on either side of the equation. $y^2 = 2y + 15$ Step 4: The equation is quadratic. $y^2 = 2y + 15$ Step 5: Rewrite the equation in standard form. $y^2 -2y-15 = 0$ Step 6: Factor. $(y +3)(y -5) = 0$ Step 7: Set each factor equal to 0. $y +3 = 0$ or $y -5 = 0$ Solve each equation. $y = -3$ or $y =+5$
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