Answer
$y = -3$ or $y =+5$
Work Step by Step
$\frac{y^2}{30} = \frac{y}{15} + \frac{1}{2}$
Step 1:
Clear the equation from fractions.
$30(\frac{y^2}{30}) = 30(\frac{y}{15} + \frac{1}{2})$
Step 2: Use the distribute property.
$y^2 = 2y + 15$
Step 3:
is not needed since no simplifying can be done on either side of the equation.
$y^2 = 2y + 15$
Step 4:
The equation is quadratic.
$y^2 = 2y + 15$
Step 5: Rewrite the equation in standard form.
$y^2 -2y-15 = 0$
Step 6: Factor.
$(y +3)(y -5) = 0$
Step 7: Set each factor equal to 0.
$y +3 = 0$ or $y -5 = 0$
Solve each equation.
$y = -3$ or $y =+5$
