Answer
$h = 1$
Work Step by Step
$\frac{2+h}{9} + \frac{h - 1}{3} = \frac{1}{3}$
Step 1: Clear the equation from fractions.
$9(\frac{2+h}{9} + \frac{h - 1}{3}) = 9(\frac{1}{3})$
Step 2: Use the distribute property.
$2+h + 3(h-1) = 3$
$2+h + 3h-3 = 3$
Step 3: simplify each side of the equation by combining like terms.
$4h - 1= 3$
Step 4: The equation is linear.
$4h - 1= 3$
Step 5: Get all variable terms on one side and all numbers on the other side by using the addition property of equality.
$4h - 1 + 1 = 3 + 1$
$4h =4$
Step 6: Get the variable alone by using the multiplication property of equality.
$4h \times \frac{1}{4} = 4 \times \frac{1}{4} $
$h = 1$
Final Step: Check each solution in the original equation.
$\frac{2+1}{9} + \frac{1 - 1}{3}= \frac{3}{9} + \frac{0}{3}= \frac{1}{3}$
