Answer
n=$-\frac{1}{2}$ or n=2
Work Step by Step
n(2n-3)=2
$2n^{2}$-3n-2=0
(2n+1)(n-2)=0
Solve
2n+1=0, 2n=-1, n=$-\frac{1}{2}$
n-2=0, n=2
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Appendix B - Exercise Set - Page 981: 30
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