Answer
$c = +1$ or $c =+4$
Work Step by Step
$\frac{c^2}{20} - \frac{c}{4} + \frac{1}{5} = 0$
Step 1:
Clear the equation from fractions.
$20(\frac{c^2}{20} - \frac{c}{4} + \frac{1}{5}) = 20\times0$
Step 2: Use the distribute property.
$c^2- 5c + 4 = 0$
Step 3:
is not needed since no simplifying can be done on either side of the equation.
Step 4:
The equation is quadratic.
$c^2- 5c + 4 = 0$
Step 5: Rewrite the equation in standard form.
$c^2 -5c+ 4 = 0$
Step 6: Factor.
$(c -1)(c -4) = 0$
Step 7: Set each factor equal to 0.
$c -1 = 0$ or $c -4 = 0$
Solve each equation.
$c = +1$ or $c =+4$
