## Algebra: A Combined Approach (4th Edition)

$x = +0.4$ or $x =-0.5$
$\frac{x^2}{2} + \frac{x}{20} = \frac{1}{10}$ Step 1: Clear the equation from fractions. $20(\frac{x^2}{2} + \frac{x}{20}) = 20 \times \frac{1}{10}$ Step 2: Use the distribute property. $10x^2 + x = 2$ Step 3: is not needed since no simplifying can be done on either side of the equation. $10x^2 + x = 2$ Step 4: The equation is quadratic. $10x^2 + x = 2$ Step 5: Rewrite the equation in standard form. $10x^2 + 1x-2 = 0$ Step 6: Factor. $(5x-2)(2x +1) = 0$ Step 7: Set each factor equal to 0. $5x -2 = 0$ or $2x +1 = 0$ Solve each equation. $5x = +2$ or $2x =-1$ $x = +0.4$ or $x =-0.5$