## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Appendix A - Exercise Set - Page 976: 63

#### Answer

Appendix A - Ex. Set : 63 (Answer) $2x^3 – 54$ $= 2(x – 3)(x^2 + 3x + 9)$

#### Work Step by Step

Appendix A - Ex. Set : 63 (Solution) $2x^3 – 54$ $= 2(x^3 – 27)$ (Factoring out the common factor) $= 2(x^3 – 3^3)$ $= 2(x – 3)(x^2 + 3x + 3^2)$ (Difference of Two Cubes) $= 2(x – 3)(x^2 + 3x + 9)$

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