## Algebra: A Combined Approach (4th Edition)

$2x(5x-2)(25x^{2}+10x+4)$
Step 1: $250x^{4}-16x$ Step 2: The two terms have a common factor of $2x$, which we factor out: $250x^{4}-16x=2x(125x^{3}-8)$. Step 3: $2x((5x)^{3}-(2)^{3})$ Step 4: $2x(5x-2)((5x)^{2}+(5x)(2)+2^{2})$ Step 5: $2x(5x-2)(25x^{2}+10x+4)$ Step 6: No further factorization possible.